LeetCode Problem
# https://leetcode.com/problems/median-of-two-sorted-arrays/description/
# https://leetcode.com/problems/median-of-two-sorted-arrays/solutions/3162206/python-ez-code-binary-search-o-logn-runtime-explained/
# Difficult Problem : revisit
# https://www.youtube.com/watch?v=q6IEA26hvXckj
# Time: log(min(n, m))
class Solution:
def findMedianSortedArrays(self, nums1: List[int], nums2: List[int]) -> float:
A, B = nums1, nums2
total = len(nums1) + len(nums2)
half = total // 2
# Binary Search only on A (A : smaller of the two arrays)
if len(B) < len(A):
A, B = B, A
l, r = 0, len(A) - 1
while True: # median is guarenteed
i = (l + r) // 2 # A
j = (
half - i - 2
) # B (why -2? j is the index of mid point (arrays are indexed at 0, j starts at 0))
# correct left partition
# these indices can be out of bounds : default val : -infinity and infinity
Aleft = A[i] if i >= 0 else float("-infinity")
Aright = A[i + 1] if (i + 1) < len(A) else float("infinity")
Bleft = B[j] if j >= 0 else float("-infinity")
Bright = B[j + 1] if (j + 1) < len(B) else float("infinity")
# partition is correct
if Aleft <= Bright and Bleft <= Aright:
# odd
if total % 2:
return min(Aright, Bright)
# even
return (max(Aleft, Bleft) + min(Aright, Bright)) / 2
elif Aleft > Bright:
r = i - 1
else:
l = i + 1