Valid Anagram¶
# https://leetcode.com/problems/valid-anagram/
# Input: s = "anagram", t = "nagaram"
# Output: true
# Time Complexity -> O(nlogn)
class Solution:
def isAnagram(self, s: str, t: str) -> bool:
# approach -> sorting both will result in the same thing (tan / nat => ant)
for x in "abcdefghijklmnopqrstuvwxyz":
if sorted(s) == sorted(t):
return True
return False